n^2+301n-7650=0

Solution for n^2+301n-7650=0 equation:

n^2+301n-7650=0

a = 1; b = 301; c = -7650;
Δ = b2-4ac
Δ = 3012-4·1·(-7650)
Δ = 121201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(301)-\sqrt{121201}}{2*1}=\frac{-301-\sqrt{121201}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(301)+\sqrt{121201}}{2*1}=\frac{-301+\sqrt{121201}}{2}
$